A) 0.1
B) 0.3
C) 0.6
D) None of these
Correct Answer: A
Solution :
Applying Kirchoff's law in following figure. At junction A : \[i+{{i}_{1}}+{{i}_{2}}=1\] .... (i) For Loop (i) \[-\,60\,i+(15+5){{i}_{1}}=0\] Þ \[{{i}_{1}}=3i\] ...(ii) For loop (2) ? (15 + 5) i1 + 10 i2 = 0 Þ i2 = i1 = (3 i) = 6i On solving equation (i), (ii) and (iii) we get i = 0.1 A Short Trick : Branch current = \[\,\text{main current }\left( \frac{\text{Resistance of opposite branch}}{\text{Total resistance}} \right)\] Þ\[i=1\times \left[ \frac{\frac{20}{3}}{\frac{20}{3}+60} \right]\] = 0.1 AYou need to login to perform this action.
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