JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoff's Law, Cells

  • question_answer
    A cell of e.m.f. \[E\] is connected with an external resistance \[R\], then p.d. across cell is \[V\].  The internal resistance of cell will be                [MNR 1987; Kerala PMT 2002; MP PMT 2002]

    A)                    \[\frac{(E-V)R}{E}\]

    B)                                      \[\frac{(E-V)R}{V}\]

    C)                    \[\frac{(V-E)R}{V}\]   

    D)            \[\frac{(V-E)R}{E}\]

    Correct Answer: B

    Solution :

               Let the current in the circuit \[=i=\frac{V}{R}\] Across the cell, \[E=V+ir\]Þ\[r=\frac{E-V}{i}=\frac{E-V}{V/R}=\left( \frac{E-V}{V} \right)\,R\]


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