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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoffs Law Cells

  • question_answer
    When a resistor of 11 W is connected in series with an electric cell, the current flowing in it is 0.5 A.  Instead, when a resistor of 5 W is connected to the same electric cell in series, the current increases by 0.4 A. The internal resistance of the cell is                                                                  [EAMCET 2001]

    A)             1.5 W                                      

    B)            2 W

    C)             2.5 W                                      

    D)            3.5 W

    Correct Answer: C

    Solution :

               By using \[i=\frac{E}{R+r}\] \[\Rightarrow 0.5=\frac{E}{11+r}\] Þ \[E=5.5+0.5r\] ..?(i) and \[0.9=\frac{E}{5+r}\] Þ \[E=4.5+0.9r\]                 ..?(ii) On solving these equation, we have \[r=2.5\Omega \]


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