A) \[{{N}_{2}}{{O}_{4}}\]⇌ \[2N{{O}_{2}}\]
B) \[2HI\]⇌\[{{H}_{2}}+{{I}_{2}}\]
C) \[2S{{O}_{2}}+{{O}_{2}}\]⇌ \[2S{{O}_{3}}\]
D) \[{{N}_{2}}+{{O}_{2}}\] ⇌ \[2NO\]
Correct Answer: C
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[\Delta n=-1\]for reaction \[2S{{O}_{2}}+{{O}_{2}}\] ⇌ \[2S{{O}_{3}}\] So for this reaction \[{{K}_{p}}\]is less than \[{{K}_{c}}\].
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