2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    Equilibrium constants \[{{K}_{1}}\]and \[{{K}_{2}}\]for the following equilibria \[NO(g)+\frac{1}{2}{{O}_{2}}\] \[\overset{{{K}_{1}}}{leftrightarrows}\]  \[N{{O}_{2}}(g)\] and \[2N{{O}_{2}}(g)\] \[\overset{{{K}_{2}}}{leftrightarrows}\] \[2NO(g)+{{O}_{2}}(g)\] are related as  [CBSE PMT 2005]

    A)                 \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]               

    B)                 \[{{K}_{2}}=K_{1}^{2}\]

    C)                 \[{{K}_{2}}=\frac{{{K}_{1}}}{2}\]               

    D)                 \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]

    Correct Answer: D

    Solution :

           \[{{K}_{1}}=\frac{[N{{O}_{2}}]}{[NO]{{[{{O}_{2}}]}^{1/2}}}\];  \[{{K}_{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\]                    \[\Rightarrow \] \[\frac{{{[N{{O}_{2}}]}^{2}}}{{{[NO]}^{2}}[{{O}_{2}}]}=\frac{1}{{{K}_{2}}}\]\[\Rightarrow \] \[\frac{[N{{O}_{2}}]}{[NO]\ {{[{{O}_{2}}]}^{1/2}}}=\frac{1}{\sqrt{{{K}_{2}}}}\]                                    \[\Rightarrow \] \[{{K}_{1}}=\frac{1}{\sqrt{{{K}_{2}}}}\]; \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner