A) \[K={K}'\]
B) \[{K}'=\sqrt{K}\]
C) \[K=\sqrt{{{K}'}}\]
D) \[K\times {K}'=1\]
Correct Answer: B
Solution :
\[{K}'={{K}^{n}};\] Hence \[n=\frac{1}{2}\] \[\therefore \,\,{K}'={{K}^{1/2}}=\sqrt{K}\]You need to login to perform this action.
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