A) \[{{(RT)}^{1/2}}\]
B) \[{{(RT)}^{-1/2}}\]
C) \[(RT)\]
D) \[{{(RT)}^{-1}}\]
Correct Answer: B
Solution :
\[{{K}_{p}}={{K}_{c}}{{[RT]}^{\Delta {{n}_{g}}}}\] \[\Delta {{n}_{g}}=1-1.5=-0.5\] \[{{K}_{p}}={{K}_{c}}{{[RT]}^{-1/2}}\] \[\therefore \,\,\frac{{{K}_{p}}}{{{K}_{c}}}={{[RT]}^{-1/2}}\]You need to login to perform this action.
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