A) \[\frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma }\]
B) \[\frac{P}{\cos \alpha }=\frac{Q}{\cos \beta }=\frac{R}{\cos \gamma }\]
C) \[\frac{P}{\tan \alpha }=\frac{Q}{\tan \beta }=\frac{R}{\tan \gamma }\]
D) \[\frac{P}{\sin \beta }=\frac{Q}{\sin \gamma }=\frac{R}{\sin \alpha }\]
Correct Answer: A
Solution :
According to Lami's theorem \[\frac{P}{\sin \alpha }=\frac{Q}{\sin \beta }=\frac{R}{\sin \gamma }\]
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