A) \[1:8\]
B) \[1:4\]
C) \[4:1\]
D) \[8:1\]
Correct Answer: D
Solution :
\[2S{{O}_{2}}(g)+{{O}_{2}}(g)\]⇌\[2S{{O}_{3}}(g)\] For \[1d{{m}^{3}}\] \[R=k{{[S{{O}_{2}}]}^{2}}[{{O}_{2}}]\] \[R=K\ {{\left[ \frac{1}{T} \right]}^{2}}\left[ \frac{1}{1} \right]=1\] For \[2d{{m}^{3}}\] \[R=K\ {{\left[ \frac{1}{2} \right]}^{2}}\left[ \frac{1}{2} \right]=\frac{1}{8}\] So, the ratio is 8 : 1You need to login to perform this action.
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