A) \[{{K}_{c}}={{[{{O}_{2}}]}^{5}}\]
B) \[{{K}_{c}}=[{{P}_{4}}{{O}_{10}}]/5[{{P}_{4}}][{{O}_{2}}]\]
C) \[{{K}_{c}}=[{{P}_{4}}{{O}_{10}}]/[{{P}_{4}}]{{[{{O}_{2}}]}^{5}}\]
D) \[{{K}_{c}}=1/{{[{{O}_{2}}]}^{5}}\]
Correct Answer: D
Solution :
\[{{P}_{4}}(s)+5{{O}_{2}}(g)\] ⇌ \[{{P}_{4}}{{O}_{10}}(s)\] \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}(s)]}{[{{P}_{4}}(s)]{{[{{O}_{2}}(g)]}^{5}}}\] We know that concentration of a solid component is always taken as unity \[{{K}_{c}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]You need to login to perform this action.
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