A) \[4/27\]
B) \[27/4\]
C) \[1/27\]
D) 24
E) 9
Correct Answer: A
Solution :
\[\underset{(a-x)}{\mathop{\overset{a}{\mathop{{{N}_{2}}}}\,}}\,+\underset{(b-3x)}{\mathop{\overset{b}{\mathop{3{{H}_{2}}}}\,}}\,\] ⇌ \[\underset{(2x)}{\mathop{\overset{0}{\mathop{2N{{H}_{3}}}}\,}}\,\] 50% Dissociation of \[{{N}_{2}}\] take place so, At equilibrium \[\frac{2\times 50}{100}=1\]; value of \[x=1\] \[{{K}_{c}}=\frac{{{[2]}^{2}}}{[1]\,{{[3]}^{3}}}=\frac{4}{27}\] so, \[{{K}_{c}}=\frac{4}{27}\]You need to login to perform this action.
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