JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    For the reaction \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌ \[2N{{H}_{3(g)}}\], the correct expression of equilibrium constant  K is [CPMT 1984, 2000]

    A)                 \[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\]                

    B)                 \[K=\frac{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}{{{[N{{H}_{3}}]}^{2}}}\]

    C)                 \[K=\frac{2[N{{H}_{3}}]}{[{{N}_{2}}]\times 3[{{H}_{2}}]}\]           

    D)                 \[K=\frac{[{{N}_{2}}]\times 3[{{H}_{2}}]}{2[N{{H}_{3}}]}\]

    Correct Answer: A

    Solution :

              \[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,\,{{[{{H}_{2}}]}^{3}}}\]


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