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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction \[A+B\]⇌\[C+D\], 2 moles of C and D are formed. The equilibrium constant for the reaction will be             [CPMT 1992]

    A)                 \[\frac{1}{4}\]   

    B)                 \[\frac{1}{2}\]

    C)                 1             

    D)                 4

    Correct Answer: C

    Solution :

                                      \[A+B\] ⇌  \[C+D\]                    Initial conc.             4,    4        0     0                    After T time conc.  (4-2) (4-2)   2     2                                 Equilibrium constant = \[\frac{[C]\,\,[D]}{[A]\,\,[B]}=\frac{2\times 2}{2\times 2}=1\]


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