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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    In a \[500ml\] capacity vessel \[CO\] and \[C{{l}_{2}}\] are mixed to form \[COC{{l}_{2}}\]. At equilibrium, it contains 0.2 moles of \[COC{{l}_{2}}\] and 0.1 mole of each of \[CO\] and \[C{{O}_{2}}\]. The equilibrium constant \[{{K}_{c}}\] for the reaction \[CO+C{{l}_{2}}\] ⇌\[COC{{l}_{2}}\] is [CBSE PMT 1998]

    A)                 5             

    B)                 10

    C)                 15          

    D)                 20

    Correct Answer: B

    Solution :

             \[CO+C{{l}_{2}}\] ⇌ \[COC{{l}_{2}}\]                    \[[CO]=\frac{0.1}{0.5}\],  \[[C{{l}_{2}}]=\frac{0.1}{0.5}\],  \[[COC{{l}_{2}}]=\frac{0.2}{0.5}\]                                 \[=\frac{[COC{{l}_{2}}]}{[CO]\,\,[C{{l}_{2}}]}=0\frac{\frac{0.2}{0.5}}{\frac{0.1}{0.5}\times \frac{0.1}{0.5}}=\frac{2}{5}\times 25=10\]


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