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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    15 moles of \[{{H}_{2}}\] and 5.2 moles of \[{{I}_{2}}\] are mixed and allowed to attain equilibrium at \[{{500}^{o}}C\]. At equilibrium, the concentration of \[HI\] is found to be 10 moles. The equilbrium constant for the formation of \[HI\] is  [KCET 2005]

    A)                 50          

    B)                 15

    C)                 100        

    D)                 25

    Correct Answer: A

    Solution :

               \[{{H}_{2}}\]    +    \[{{I}_{2}}\]     ⇌    \[2HI\]                    15             5.2               0                    (15?5)      (5.2?5)         10                                 \[{{K}_{C}}=\frac{{{[HI]}^{2}}}{[{{H}_{2}}][{{I}_{2}}]}=\frac{10\times 10}{10\times 0.2}=50\]


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