A) 20.2
B) 25.4
C) 0.284
D) 11.1
Correct Answer: D
Solution :
\[\underset{0.4-0.25\ =\ 0.15}{\mathop{\underset{0.4}{\mathop{{{H}_{2}}}}\,}}\,\]\[+\] \[\underset{0.4-0.25\ =\ 0.15/2}{\mathop{\underset{0.4}{\mathop{{{I}_{2}}}}\,}}\,\]⇌ \[\underset{0.50/2}{\mathop{\underset{0.50\,\,\,\,}{\mathop{2HI\,\,\,\,}}\,}}\,\] \[{{K}_{c}}=\frac{{{[HI]}^{2}}}{[{{H}_{2}}][{{I}_{2}}]}=\frac{{{\left[ \frac{0.5}{2} \right]}^{2}}}{\left[ \frac{0.15}{2} \right]\,\left[ \frac{0.15}{2} \right]}\] \[=\frac{0.5\times 0.5}{0.15\times 0.15}=11.11\]
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