A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) 1
D) 4
Correct Answer: C
Solution :
\[A+B\] ⇌ \[C+D\] Initial conc. 4, 4 0 0 After T time conc. (4-2) (4-2) 2 2 Equilibrium constant = \[\frac{[C]\,\,[D]}{[A]\,\,[B]}=\frac{2\times 2}{2\times 2}=1\]You need to login to perform this action.
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