A) \[litr{{e}^{-1}}\,mol{{e}^{-1}}\]
B) \[litre\,mol{{e}^{-1}}\]
C) \[mol{{e}^{2}}\,litr{{e}^{-2}}\]
D) \[mole\,litr{{e}^{-1}}\]
Correct Answer: B
Solution :
\[K=\frac{[{{C}_{2}}{{H}_{6}}]}{[{{C}_{2}}{{H}_{4}}]\,\,[{{H}_{2}}]}=\frac{[mole/litre]}{[mole/litre]\,\,[mole/litre]}\] = litre/mole. or litre mole?1.You need to login to perform this action.
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