A) 0.30
B) 0.18
C) 0.17
D) 0.11
Correct Answer: D
Solution :
\[\underset{\text{a}-\text{x}}{\mathop{\underset{\text{a}}{\mathop{N{{H}_{4}}HS}}\,}}\,\] ⇌ \[\underset{0.5+\text{x}\,\,\,\,\,\,\,\,\,\,\,\text{x}\,\,\,\,\,\,}{\mathop{\underset{0.5\text{atm}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{N{{H}_{3\,(g)}}+{{H}_{2}}{{S}_{(g)}}}}\,}}\,\] Total pressure \[=0.5+2x=0.84\] i.e., \[x=0.17\] \[{{K}_{p}}={{P}_{N{{H}_{3}}}}.{{P}_{{{H}_{2}}S}}\] \[=(0.67).\,(0.17)\]=0.1139You need to login to perform this action.
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