JEE Main & Advanced
Chemistry
Equilibrium / साम्यावस्था
Question Bank
Law of equilibrium and Equilibrium constant
question_answer
A reaction is \[A+B\to C+D\]. Initially we start with equal concentration of \[A\] and \[B\]. At equilibrium we find the moles of \[C\] is two times of \[A\]. What is the equilibrium constant of the reaction [BHU 1998; KCET 2000]
A) 4
B) 2
C) \[1/4\]
D) \[1/2\]
Correct Answer:
A
Solution :
A+ B ⇌ C+ D at equilibrium a a 2a 2a \[K=\frac{2a\times 2a}{a\times a}=4\]