A) \[3.3\times {{10}^{2}}\]\[mol\,\,litr{{e}^{-1}}\]
B) \[3\times {{10}^{-1}}\]\[mol\,\,litr{{e}^{-1}}\]
C) \[3\times {{10}^{-3}}\]\[mol\,\,litr{{e}^{-1}}\]
D) \[3\times {{10}^{3}}\]\[mol\,\,litr{{e}^{-1}}\]
Correct Answer: C
Solution :
\[K=\frac{{{[N{{O}_{2}}]}^{2}}}{[{{N}_{2}}{{O}_{4}}]}\]\[=\frac{{{[1.2\times {{10}^{-2}}]}^{2}}}{[4.8\times {{10}^{-2}}]}\]\[=0.3\times {{10}^{-2}}\]\[=3\times {{10}^{-3}}\]You need to login to perform this action.
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