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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    For the system \[A(g)+2B(g)\]⇌\[C(g)\], the equilibrium concentrations are  0.06 mole/litre  0.12 mole/litre  0.216 mole/litre. The \[{{K}_{eq}}\] for the reaction is [CPMT 1983]

    A)                 250        

    B)                 416

    C)                 \[4\times {{10}^{-3}}\]  

    D)                 125

    Correct Answer: A

    Solution :

               For reaction  A + 2B ⇌ C                                 \[K=\frac{[C]}{[A]\,\,{{[B]}^{2}}}=\frac{0.216}{0.06\times 0.12\times 0.12}=250\].


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