Answer:
As the particle remains stationary under the action of the three forces, so \[{{\vec{F}}_{1}}+{{\vec{F}}_{2}}+{{\vec{F}}_{3}}=0\]When force \[{{\vec{F}}_{1}}\]is removed, the net force left is \[{{\vec{F}}_{2}}+{{\vec{F}}_{3}}=-{{\vec{F}}_{1}}\] Acceleration, \[a=-\frac{{{{\vec{F}}}_{1}}}{m}.\]
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