A) 21
B) 24
C) 22
D) 18
Correct Answer: D
Solution :
[d] LCM of 5, 6, 7 and 8 = 840 Then, the smaller number \[(x)=840\times k+3\] (divided by 9) \[=840\times 2+3(put\,k=2)=1680+3=1683\] \[\therefore \] Required sum \[=1+6+8+3=18\] |
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