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SSC Quantitative Aptitude LCM & HCF Question Bank LCM and HCF (I)

  • question_answer
    GCD or HCF of \[{{(a+b-c)}^{6}}\] and \[{{(a+b-c)}^{4}}\] is

    A) \[{{(a+b-c)}^{6}}\]

    B) \[{{(a+b-c)}^{2}}\]

    C) \[{{(a+b-c)}^{10}}\]

    D) \[{{(a+b-c)}^{4}}\]

    Correct Answer: D

    Solution :

    [d] GCD is \[{{(a+b-c)}^{4}}\] because \[{{(a+b-c)}^{4}}\] is greatest common in \[{{(a+b-c)}^{4}}\] and \[{{(a+b-c)}^{6}}.\]


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