A) \[\frac{1}{13}\]
B) \[\frac{1}{5}\]
C) \[\frac{1}{15}\]
D) \[\frac{1}{25}\]
Correct Answer: C
Solution :
| [c] We know that, HCF of fractions \[=\frac{\text{HCF of numerators}}{\text{LCM of denominators}}\] \[\therefore \] Required HCF \[=\frac{\text{HCF}\,\,\text{of}\,\,\text{4}\,\,\text{and}\,\,\text{7}}{\text{LCM}\,\,\text{of}\,\,\text{5}\,\,\text{and}\,\,15}=\frac{1}{15}\] |
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