question_answer

The least number of square tiles required to pave the ceiling of a room 15 m 17 cm long and 9 m 2 cm broad, is

A) 656

B) 738

C) 814

D) 902

Correct Answer: C

Solution :

[c] Side of each square tile = HCF of 1517 cm and 902 cm = 41 cm Required number of tiles             \[=\left( \frac{1517\times 902}{41\times 41} \right)=814\]