A) 64
B) 124
C) 156
D) 260
Correct Answer: A
Solution :
[a] Required number = HCF of \[(1354-10),\,(1866-10)\] and \[(2762-10)\] = HCF of 1344, 1856, 2752 = HCF of \[({{2}^{6}}\times 3\times 7),\]\[({{2}^{6}}\times 29),\]\[({{2}^{6}}\times 43)={{2}^{6}}=64\] |
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