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SSC Quantitative Aptitude LCM & HCF Question Bank LCM and HCF (II)

  • question_answer
    Let x be the least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case but when divided by 9 leaves no remainder. The sum of digits of x is [SSC CGL Tier II, 2015]

    A) 21

    B) 24

    C) 22

    D) 18

    Correct Answer: D

    Solution :

    [d] LCM of 5, 6, 7 and 8 = 840 Then, the smaller number \[(x)=840\times k+3\] (divided by 9) \[=840\times 2+3(put\,k=2)=1680+3=1683\] \[\therefore \] Required sum \[=1+6+8+3=18\]


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