A) \[{{(a+b-c)}^{6}}\]
B) \[{{(a+b-c)}^{2}}\]
C) \[{{(a+b-c)}^{10}}\]
D) \[{{(a+b-c)}^{4}}\]
Correct Answer: D
Solution :
[d] GCD is \[{{(a+b-c)}^{4}}\] because \[{{(a+b-c)}^{4}}\] is greatest common in \[{{(a+b-c)}^{4}}\] and \[{{(a+b-c)}^{6}}.\]You need to login to perform this action.
You will be redirected in
3 sec