A)
B)
C)
D)
Correct Answer: A
Solution :
Using law of reflection, \[\because \angle i=\angle r={{90}^{o}}-{{50}^{o}}={{40}^{o}}\] So, \[\angle NCB={{40}^{o}}\] \[\angle BCA={{90}^{o}}-{{40}^{o}}={{50}^{o}}\] In \[\Delta ABC={{180}^{o}}-{{40}^{o}}-{{50}^{o}}={{90}^{o}}\] |
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