A) 28
B) 30
C) 32
D) 34
Correct Answer: B
Solution :
According to laws of reflection, \[\angle i=\angle r\] So, \[\angle PQO={{30}^{o}}\] Given, \[PQ=0.2\,m\] \[\tan {{30}^{o}}=\frac{OP}{PQ}\] \[\Rightarrow \] \[\frac{1}{\sqrt{3}}=\frac{OP}{0.2}\Rightarrow OP=\frac{0.2}{\sqrt{3}}m\] OP is distance covered by the ray in one reflection. |
Number of times the ray undergoes reflections, before it emerges out \[=\frac{2\sqrt{3}}{OP}=\frac{2\sqrt{3}}{\frac{0.2}{\sqrt{3}}}=\frac{6}{0.2}=30\] |
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