A) On the left side, 30 cm, real, inverted and magnified
B) On the left side, 20 cm, virtual, upright and diminished
C) On the right side, 30 cm, real, inverted and magnified
D) On the right side, 20 cm, virtual, up- right and diminished
Correct Answer: A
Solution :
\[\frac{1}{v}+\frac{1}{u}=\frac{1}{f},\]we get: \[\frac{1}{v}+\frac{1}{-15}=\frac{1}{-10}\] \[\frac{1}{v}=\frac{+2-3}{30},\frac{1}{v}=\frac{-1}{30}\] So, image distance, v = -30 cm on the left side of the mirror. It is real, inverted and magnified.You need to login to perform this action.
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