Answer:
Size of object,\[O=2.5\text{ }m=250\text{ }cm\] Width of pin hole camera, \[v=24\text{ }cm\] Size of the image,\[I=1.2\text{ }cm\] Object distance,\[u=?\] We know that, \[m=\frac{v}{u}=\frac{I}{O}\Rightarrow \frac{v}{u}=\frac{I}{O}\]On substitution, we get, \[u=50000cm=50\text{ }m.\]
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