A) \[-\text{2}.\text{14}{}^\circ \]
B) \[+\text{2}.\text{14}{}^\circ \]
C) \[-\text{4}.\text{12}{}^\circ \]
D) \[+\text{4}.\text{12}{}^\circ \]
Correct Answer: C
Solution :
For direct vision spectroscope, \[{{\delta }_{1}}+{{\delta }_{2}}=0\] \[\therefore \] \[({{\mu }_{1}}-1){{A}_{1}}+({{\mu }_{2}}-1){{A}_{2}}=0\] \[\Rightarrow \] \[{{A}_{2}}=-\left[ \frac{{{\mu }_{1}}-1}{{{\mu }_{2}}-1} \right]{{A}_{1}}\] \[=-\left[ \frac{1\cdot 52-1}{1\cdot 63-1} \right]\times {{5}^{o}}\mathbf{=-4}\mathbf{.1}{{\mathbf{2}}^{\mathbf{o}}}\]You need to login to perform this action.
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