A) \[30{}^\circ \]
B) \[40{}^\circ \]
C) \[50{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: C
Solution :
The situation is as shown in figure: The reflected ray makes an angle, \[100-\theta \]with the normal. This is also equal to\[\theta \]. \[\therefore \] \[100-\theta =\theta \] \[\Rightarrow \] \[\theta ={{50}^{o}}\]You need to login to perform this action.
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