A) \[45{}^\circ \]
B) \[75{}^\circ \]
C) \[90{}^\circ \]
D) \[120{}^\circ \]
Correct Answer: C
Solution :
Let the angle between total deviation for the ray mirrors be\[\theta \], then For the resultant ray to be parallel, \[\delta \] should be\[{{180}^{o}}\] \[\therefore \] \[360-2({{i}_{1}}+{{i}_{2}})={{180}^{o}}\] \[\Rightarrow \] \[({{i}_{1}}+{{i}_{2}})={{90}^{o}}\] From the geometry of figure, \[90-{{i}_{1}}+90-{{i}_{2}}+\theta =180\] \[\therefore \] \[{{i}_{1}}+{{i}_{2}}=\theta \] Hence, angle between the mirror should be\[{{90}^{o}}\].You need to login to perform this action.
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