A) \[{{\sin }^{-1}}\frac{1}{2}\]
B) \[{{\sin }^{-1}}\left( \frac{5}{6} \right)\]
C) \[{{\sin }^{-1}}\frac{5}{12}\]
D) \[{{\sin }^{-1}}\left( \frac{1}{\sqrt{2}} \right)\]
Correct Answer: B
Solution :
\[\sin C=\frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{Velocity\,\,of\,\,light\,\,in\,\,1st\,\,medium}{Velocity\,\,of\,light\,\,in\,\,2nd\,\,medium}\]where, \[C=\] critical angle \[\therefore \] \[\sin C=\frac{2\cdot 0\times {{10}^{10}}}{2\cdot 4\times {{10}^{10}}}=\frac{20}{24}=\frac{5}{6}\] \[\Rightarrow \] \[C\mathbf{=si}{{\mathbf{n}}^{\mathbf{-1}}}\frac{\mathbf{5}}{\mathbf{6}}\]You need to login to perform this action.
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