A) \[\frac{\mu }{\sqrt{{{h}^{2}}-1}}\]
B) \[\mu \sqrt{{{h}^{2}}-1}\]
C) \[h\sqrt{{{\mu }^{2}}-1}\]
D) \[\frac{h}{\sqrt{{{\mu }^{2}}-1}}\]
Correct Answer: D
Solution :
Referring figure,\[C=\frac{r}{h}\] where, \[C=\] critical angle \[r=h\tan C=h(\sin C/\cos C)=\frac{h\sin C}{\sqrt{1-{{\sin }^{2}}C}}\] We know,\[\sin C=\frac{1}{\mu }\] \[\therefore \] \[r=\frac{h/\mu }{\sqrt{1-\frac{1}{{{\mu }^{2}}}}}=\frac{h}{\sqrt{{{\mu }^{2}}-1}}\]You need to login to perform this action.
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