A) 0
B) 1
C) 2
D) 4
Correct Answer: A
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\,\,\frac{x\,.\,2\,{{\sin }^{2}}x}{{{x}^{2}}}=2.\underset{x\to 0}{\mathop{\lim }}\,{{\left( \frac{\sin x}{x} \right)}^{2}}\cdot \underset{x\to 0}{\mathop{\lim }}\,x=0\].
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