A) 1
B) ?1
C) 0
D) None of these
Correct Answer: C
Solution :
On rationalising, we get \[\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{{{x}^{2}}+1-{{x}^{2}}}{\sqrt{{{x}^{2}}+1}+x}=\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{1}{\sqrt{{{x}^{2}}+1}+x}=0.\]
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