JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,\sqrt{\frac{x+\sin x}{x-\cos x}}=\] [Roorkee 1994]

    A)                 0

    B)                 1

    C)                 ?1

    D)                 None of these

    Correct Answer: B

    Solution :

                       \[\underset{x\to \infty }{\mathop{\lim }}\,\,\,\sqrt{\left( \frac{x+\sin x}{x-\cos x} \right)}=\underset{x\to \infty }{\mathop{\lim }}\,\,\sqrt{\left( \frac{1+\frac{\sin x}{x}}{1-\frac{\cos x}{x}} \right)}=\underset{x\to \infty }{\mathop{\lim }}\,\sqrt{1}=1\] \[[\,\because \,\,\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{\sin x}{x}\] and \[\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{\cos x}{x}\] both are equal to 0]


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