A) e
B) \[\frac{1}{e}\]
C) \[{{e}^{2}}\]
D) None of these
Correct Answer: C
Solution :
\[{{\left[ \underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{1}{x/2} \right)}^{x/2}} \right]}^{2}}={{e}^{2}}.\]
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