A) 1
B) ?1
C) \[{{e}^{2}}\]
D) \[e\]
Correct Answer: C
Solution :
Given limit \[=\underset{x\to 0}{\mathop{\lim }}\,\,\,{{\left( \frac{1+\tan x}{1-\tan x} \right)}^{1/x}}\] \[=\underset{x\to 0}{\mathop{\lim }}\,\,\,\frac{{{\{{{(1+\tan x)}^{1/\tan x}}\}}^{(\tan x)/x}}}{{{\{{{(1-\tan x)}^{1/\tan x}}\}}^{(\tan x)/x}}}=\frac{e}{{{e}^{-1}}}={{e}^{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
