JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to 1}{\mathop{\lim }}\,\frac{(2x-3)(\sqrt{x}-1)}{2{{x}^{2}}+x-3}=\]                                             [IIT 1977]

    A)                 ?1/10

    B)                 1/10

    C)                 ?1/8

    D)                 None of these

    Correct Answer: A

    Solution :

                    \[\underset{x\to 1}{\mathop{\lim }}\,\,\,\frac{(2x-3)\,(\sqrt{x}-1)\times (\sqrt{x}+1)}{(x-1)\,(2x+3)\times (\sqrt{x}+1)}=\frac{-1}{5\,.\,2}=\frac{-1}{10}.\]


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