A) \[0\]
B) \[1\]
C) \[\frac{1}{n}\]
D) \[\frac{1}{n!}\]
Correct Answer: A
Solution :
\[\text{ }\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{\log x}{{{x}^{n}}}=\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{1}{n{{x}^{n}}}=0\] (By L-Hospital's rule)
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