A) 0
B) 1/10
C) 1/5
D) 3/10
Correct Answer: D
Solution :
\[\underset{x\to \infty }{\mathop{\lim }}\,\,\,\frac{(2x-3)\,\,(3x-4)}{(4x-5)\,\,(5x-6)}\] \[=\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{x}^{2}}\left( 2-\frac{3}{x} \right)\,\left( 3-\frac{4}{x} \right)}{{{x}^{2}}\left( 4-\frac{5}{x} \right)\,\left( 5-\frac{6}{x} \right)}=\frac{6}{20}=\frac{3}{10}\].
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