JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left[ 1+\frac{1}{mx} \right]}^{x}}\]equal to              [Kurukshetra CEE 1998]

    A)                 \[{{e}^{1/m}}\]

    B)                 \[{{e}^{-1/m}}\]

    C)                 \[{{e}^{m}}\]

    D)                 \[{{m}^{e}}\]

    Correct Answer: A

    Solution :

                       Let \[y=\underset{x\to \,\infty }{\mathop{\lim }}\,\,{{\left( 1+\frac{1}{mx} \right)}^{x}}=\underset{x\to \,\infty }{\mathop{\lim }}\,\,{{\left( 1+\frac{1}{mx} \right)}^{mx\cdot \frac{1}{m}}}\]                 \[\Rightarrow \,\,y={{e}^{1/m}},\,\,\,\left( \because \underset{x\to \,\infty }{\mathop{\lim }}\,\,{{\left( 1+\frac{1}{x} \right)}^{x}}=e \right)\].


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