JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    The value of the limit of \[\frac{{{x}^{3}}-{{x}^{2}}-18}{x-3}\]as x tends to 3 is [SCRA 1996]

    A)                 3

    B)                 9

    C)                 18

    D)                 21

    Correct Answer: D

    Solution :

                       Let \[y=\underset{x\to 3}{\mathop{\lim }}\,\,\,\frac{{{x}^{3}}-{{x}^{2}}-18}{x-3}\],       \[\left( \frac{0}{0}\,\text{form} \right)\]            Applying L-Hospital's rule, we get                                 \[y=\underset{x\to 3}{\mathop{\lim }}\,\,\,3{{x}^{2}}-2x=(27-6)=21\].


You need to login to perform this action.
You will be redirected in 3 sec spinner