A) Does not exist
B) Is equal to ? 3/2
C) Is equal to 3/2
D) Is equal to 3
Correct Answer: D
Solution :
\[\underset{h\to 0}{\mathop{\lim }}\,\frac{f(2h+2+{{h}^{2}})-f(2)}{f(h-{{h}^{2}}+1)-f(1)}=\underset{h\to 0}{\mathop{\lim }}\,\frac{{f}'(2h+2+{{h}^{2}})(2+2h)}{{f}'(h-{{h}^{2}}+1)(1-2h)}\] \[=\frac{6\times 2}{4\times 1}=3\].You need to login to perform this action.
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